- #1
AN630078
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- Homework Statement
- Below I have attached a revision question on the wave interference of sound waves from two speakers. I have also attached the original question diagram in addition to my own diagrams to answer the questions. However, I feel this is one of my weaker topics and I am rather uncertain of the credibility of the diagrams I have drawn and my method to find the path difference in question 2. I would very much appreciate any feedback or improvements I could make, especially if tasked with drawing similar diagrams in the future. I am sorry this is rather a long thread, I only grouped the questions together since they are on a similar topic and I felt that any mistakes I may make in my earlier diagrams may continue into my subsequent solutions, so identifying their source may help in improving my approach.
Two speakers are being used to experiment with the superposition of waves, throughout which they are coherent.
Question 1; Initially the speakers are positioned 16 m apart.
a. Taking the speed of sound to be 340 ms-1 and the frequency of the source to be 85 Hz, calculate the wavelength.
b. Make a copy of the diagram and represent the compressions and rarefactions as whole and dashed lines respectively. Remember that the waves will radiate outwards, so you may want to use compasses to draw them. Mark several areas of constructive interference and destructive interference. Make your diagram to scale.
Question 2; Calculate the path difference for the second minimum from the centre. Use your
drawing to check.
Question 3; During the second experiment, the speakers are placed 4 m apart from each other. Now they oriented so that are both pointing in the same direction. The frequency is kept the same.
a. A person stands at point P 10 m from Speaker A and 8 m from Speaker B. Would the person hear a loud or quiet sound? Drawing a diagram may help.
b. If the person were to walk parallel to the speakers while someone increased the frequency, what effect, if any, would this have?
- Relevant Equations
- λ=v/f
Question 1:
a. λ=v/f
λ= 340/85
λ=4 m
b. Please see attached. Ihave tried to accurately and to scale construct a diagram representing the compressions and rarefactions of the sound waves. Since the wavelength of a wave is simply the length of one complete wave cycle, and I have found that the wavelength here is equal to 4m, I have drawn a compression every 4cm and a rarefaction every 4cm, so they are spaced with 2cm between them as a complete wavelength encompasses a compression and rarefaction, like a peak and trough in a transverse wave.
When two waves superpose in phase, they constructively interfere and produce a larger amplitude wave, which I have marked with dots in my drawing. When two waves superpose that are out of phase, they produce a smaller or zero-amplitude wave, these areas I have marked with crosses.
I have tried not to include too many overlapping compressions and rarefactions and must note that my diagram is already a little rough so I did not want to make it too messy.
I would very much appreciate any suggestions to improve my diagram and any comments as to whether my method of drawing it to scale would be correct.
Question 2:
I am not certain how to accomplish this, where the question states the "second minimum from the centre" does it mean the second trough from the centre, where a trough corresponds to a rarefaction? I have marked where this may be with a purple arrow on my diagram but I am not sure specifically where the question is referring to, which is causing me some confusion.
If this is the correct position, then to calculate the path difference (being the difference in distance traveled by the two waves from their respective sources to a given point on the pattern) would this be the difference between the wavelength of the wave emitted from the LH speaker and the difference between the wavelength of the wave from the RH speaker?
If this is the case, then the wavelength of the LH speaker at the purple arrow is 12cm=12m and the wavelength of the RH speaker is 4cm=4m (which hopefully you can see from my diagram).
Thus, the path difference would be equal to 12cm-4cm =8cm = 8m
Question 3:
a. Please see my diagram attached. I think that a person standing at point P will hear a quiet sound, as the wave from speaker (a compression) superposes the wave from B (a rarefaction) meaning the waves are out of phase, resulting in destructive interference to produce a smaller amplitude wave. If the two waves are exactly out-of-phase, meaning their phase difference is 180 degrees, then the resultant is a zero amplitude wave. Since the amplitude of a sound wave determines its loudness or volume, the decreased amplitude will reduce the noise heard by the person at point P from the speakers.
b.
The frequency is the number of complete wave cycles per second and corresponds to the pitch of the sound one would hear. Therefore, by increasing the frequency of the speakers a person walking parallel to the speakers would hear a higher pitched noise as the frequency was increased.
Moreover, the wave equation, v=f*λ shows that providing v remains constant, any increase in frequency must cause a reduction in wavelength, increasing the pitch. By increasing the frequency, on a time axis, the sound wave should compress and you can hear the sound at faster speed.
Do you think that the question was hinting about the changes to pitch here or have I answered along the wrong train of thought?
a. λ=v/f
λ= 340/85
λ=4 m
b. Please see attached. Ihave tried to accurately and to scale construct a diagram representing the compressions and rarefactions of the sound waves. Since the wavelength of a wave is simply the length of one complete wave cycle, and I have found that the wavelength here is equal to 4m, I have drawn a compression every 4cm and a rarefaction every 4cm, so they are spaced with 2cm between them as a complete wavelength encompasses a compression and rarefaction, like a peak and trough in a transverse wave.
When two waves superpose in phase, they constructively interfere and produce a larger amplitude wave, which I have marked with dots in my drawing. When two waves superpose that are out of phase, they produce a smaller or zero-amplitude wave, these areas I have marked with crosses.
I have tried not to include too many overlapping compressions and rarefactions and must note that my diagram is already a little rough so I did not want to make it too messy.
I would very much appreciate any suggestions to improve my diagram and any comments as to whether my method of drawing it to scale would be correct.
Question 2:
I am not certain how to accomplish this, where the question states the "second minimum from the centre" does it mean the second trough from the centre, where a trough corresponds to a rarefaction? I have marked where this may be with a purple arrow on my diagram but I am not sure specifically where the question is referring to, which is causing me some confusion.
If this is the correct position, then to calculate the path difference (being the difference in distance traveled by the two waves from their respective sources to a given point on the pattern) would this be the difference between the wavelength of the wave emitted from the LH speaker and the difference between the wavelength of the wave from the RH speaker?
If this is the case, then the wavelength of the LH speaker at the purple arrow is 12cm=12m and the wavelength of the RH speaker is 4cm=4m (which hopefully you can see from my diagram).
Thus, the path difference would be equal to 12cm-4cm =8cm = 8m
Question 3:
a. Please see my diagram attached. I think that a person standing at point P will hear a quiet sound, as the wave from speaker (a compression) superposes the wave from B (a rarefaction) meaning the waves are out of phase, resulting in destructive interference to produce a smaller amplitude wave. If the two waves are exactly out-of-phase, meaning their phase difference is 180 degrees, then the resultant is a zero amplitude wave. Since the amplitude of a sound wave determines its loudness or volume, the decreased amplitude will reduce the noise heard by the person at point P from the speakers.
b.
The frequency is the number of complete wave cycles per second and corresponds to the pitch of the sound one would hear. Therefore, by increasing the frequency of the speakers a person walking parallel to the speakers would hear a higher pitched noise as the frequency was increased.
Moreover, the wave equation, v=f*λ shows that providing v remains constant, any increase in frequency must cause a reduction in wavelength, increasing the pitch. By increasing the frequency, on a time axis, the sound wave should compress and you can hear the sound at faster speed.
Do you think that the question was hinting about the changes to pitch here or have I answered along the wrong train of thought?