What Is the Coefficient of Kinetic Friction and the Boy's Acceleration Downhill?

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SUMMARY

The discussion focuses on calculating the coefficient of kinetic friction and the boy's acceleration while sliding down a hill with a sled. The boy drags a 60.0-N sled up a 15-degree incline using a 25-N force at a 35-degree angle to the horizontal. To find the coefficient of kinetic friction, participants emphasize the need to analyze the forces acting parallel to the slope, concluding that the sum of these forces equals zero when the sled moves at constant speed. The acceleration down the slope can be determined after calculating the frictional force and normal force.

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a boy drags his 60.0-N sled at constant speed up a 15(degree) hill. he does so by pulling with a 25-N force on a rope attached to the sled. if the rope is inclined at 35(degree) to the horizontal, (a) what is the coefficient of kinectic friction between sled and snow? (b) At the top of the hill, he jumps on the sled and slides down the hill. What is the magnitude of his acceleration downthe slope.


i think the whole using the angles to solve the problem is throwing me off. midterms are later today. please help

i drew the diagram and everything, yet it is hard for me to relate coefficeint of kinectic friction.
 
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If the sled is moving up the at a constant speed then the total of the forces parallel to the slope is 0. With the angles, find the components of the tension,fricton,and weight along this axis (paralell to the slope) and write an equation (F1+F2+F3=0) this should let you find the friction. With the friction and normal you can then solve th problem
 

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