But what happens when the object is on an inclined surface?

[frigid]

But what happens when the object is on an inclined surface?

In this particuliar situation a 30kg block with an area of force of 80cm squared is standing on a surface which 30 degrees inclined relative to the floor. How do you calculate the pressure it exerts?

 

[Pyrrhus]

You need to find the component of the force that is normal to the surface where it acts, in order to find the pressure.

 

[frigid]

Ok so Fn/Fg = cos(30deg) = 0.866
0.866 * 30kg * 9.8 = 254.6N
254.6 / 0.008m^2 = 3.2 X 10^4

Like this?

 

[Pyrrhus]

Good work, that's it! , btw N/m^2 = Pa (Pascal).