Solve 2^27841 mod 34 by Hand: Discrete Math Problem Solution

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Homework Help Overview

The discussion revolves around solving the expression 2^27841 mod 34, situated within the context of discrete mathematics. Participants are exploring various methods and theorems applicable to modular arithmetic.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster seeks guidance on applying a specific theorem for the problem. Some participants discuss the factorization of 27841 and the implications of using Euler's totient theorem, while others inquire about alternative methods without changing the base.

Discussion Status

Participants are actively engaging with the problem, sharing insights about factorization and theorems. Some have proposed a potential solution using modular arithmetic, while others are exploring different approaches. There is no explicit consensus yet, but several lines of reasoning are being examined.

Contextual Notes

Participants note that 34 and 2 are not co-prime, which affects the applicability of certain theorems. The original poster has indicated familiarity with the relevant theorem but is struggling with its application.

raross
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could someone show me how u would solve 2^27841 mod 34 by hand? I know what theorem to use, I am just having trouble using it? Thanks
 
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What theorem would you use? Anyways, if it helps, 27841 = 11x2531 and 34 = 2x17. I found that 11 was a factor of 27841 by trial and error, and then by a lot more trial and error, found that 2531 is prime. Hopefully I didn't make a mistake in the calculations.
 
Is there any other way to do this without changing the base?
 
Euler's totient theorem?
Is a bit tricky because 34 and 2 are not co-prime.
but
[tex]2^{17} \equiv 2 \mod 34[/tex]
Then we can use that
[tex]27841 \equiv 1 \mod 16[/tex]
to get
[tex]2^{27841} \equiv 2^{1} \equiv 2 \mod 34[/tex]
 
hrm yeah that works. How would you solve it with modular exponentiation?
 

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