Finding Derivative, but wrong sign

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SUMMARY

The discussion centers on the misapplication of the quotient rule in calculus, specifically in finding derivatives. The user incorrectly placed a negative sign in their derivative calculation, leading to confusion. The correct application of the quotient rule, defined as \(\frac{d}{dx}\left(\frac{f}{g}\right)=\frac{f'g-fg'}{g^2}\), emphasizes the importance of the order of terms in the numerator. This highlights a common pitfall in calculus that can significantly affect the outcome of derivative calculations.

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  • Understanding of basic calculus concepts, particularly derivatives.
  • Familiarity with the quotient rule for differentiation.
  • Knowledge of exponential functions, specifically \(e^x\).
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  • Practice derivative calculations involving exponential functions.
  • Review common mistakes in derivative calculations and how to avoid them.
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Students learning calculus, particularly those struggling with derivative calculations and the application of the quotient rule.

gr3g1
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Ok, I am doing my calculus homework, but sometimes I get a negative in the wrong place...
Here is an example:
The solution I got for the derivative attached is on the numerator:
5e^x(9e^x)-5e^x(4+9e^x)
In the solution, the negative sign is on the other side??
I don't get it
 

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You are probably misapplying the quotient rule, which is:

[tex]\frac{d}{dx}\left(\frac{f}{g}\right)=\frac{f'g-fg'}{g^2}[/tex]

It does matter in which order you place the terms in the numerator.
 
Damn!
I didnt know that! Thanks a lot man!
 

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