How Is Work Calculated When Lifting and Carrying a Cement Block?

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SUMMARY

The work done by a person lifting a 5.5 kg cement block a vertical distance of 1.2 m is calculated using the formula W = F × d, where F is the force (weight of the block) and d is the distance lifted. The force exerted by gravity is 54.0 N (5.5 kg × 9.8 m/s²). The work done against gravity is 64.8 J (54.0 N × 1.2 m). When carrying the block horizontally for 7.3 m, the work done by the person is zero since the force of gravity acts vertically and does not contribute to horizontal displacement.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concept of work in physics
  • Knowledge of force and weight calculations
  • Basic grasp of vector components and dot products
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A person lifts a 5.5 kg cement block a vertical distance 1.2 m and then carries the block horizontally a distance 7.3 m. Determine the work done by the person and by the force of gravity in this process. How much work is done by the person and the force of gravity?

Would you break this up into components?
 
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Its not necessary if you recall the definition of work to involve a dot product.
 

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