View Full Version : work and a cylinder
ViewtifulBeau
Nov6-05, 05:23 PM
A homogeneous cylinder of radius 30cm and mass 40kg is rolling without slipping along a horizontal floor at 2.4m/s. How much work is needed to stop the cylinder?
work = delta_KE in this case so oi figured .5 *40 * 2.4^2 = 115 J but this is not right, what should i do with the cylinder?
ViewtifulBeau
Nov6-05, 07:32 PM
i still can not figure this one out.
lightgrav
Nov6-05, 08:35 PM
Besides KE of the center-of-mass moving in translation (linear),
you also have KE of the extended mass moving AROUND the c.o.m.
KE_rotation = 1/2 I (omega)^2
ViewtifulBeau
Nov6-05, 09:10 PM
i did this and found omega to be 8 rad/s and I to be 1.8 then i found the KE to be 57.6 this is now right either.
lightgrav
Nov6-05, 09:45 PM
"Besides" the old linear KE there's now rotational KE, ALSO.
The total KE is the SUM : KE_linear + KE_rotation
vBulletin® v3.8.7, Copyright ©2000-2012, vBulletin Solutions, Inc.