Does the Equation Vout=-Iin*Rf Always Apply in Current-to-Voltage Converters?

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SUMMARY

The equation Vout = -Iin * Rf applies in current-to-voltage converters, where Rf is the feedback resistor. In the discussed circuit, Rf is set to 1 k ohm, and varying the input current (Iin) from 1 to 7 amps will still yield accurate results according to this equation. However, it is crucial to note that most operational amplifiers (op-amps) operate within a current range of 1-10 mA, which may limit the practical application of this equation at higher currents. Additionally, the voltage adder and inverting amplifier can be analyzed similarly as current-to-voltage converters, confirming the versatility of the equation.

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Midas_Touch
I have attached a diagram of the circuit I have a question about.

In this current-to-voltage converter circuit, Rf = 1 k ohm. I was wondering if v out would equal Vout=-Iin*Rf where I in is the input current. If I varied the current, say 1-7 amps, would the above equation apply? How about if I varied the Rf? Would the same equation still apply?

Also, since the voltage adder and the inverting amplifier are similar to the current-voltage converter, how can I show that those circuits can be analyzed as current to voltage converter, as in vout = Iin*Rf?

I'd appreciate any suggestions...
 

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Well, yes, except that most opamps are run in the 1-10mA range. Other than that, you are on track.
 

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