Sofia_S
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"Prove that in a triangle it is in effect sinA/a=sinB/b=sinC/c
Please help me...
Please help me...
The discussion revolves around proving the sine rule for triangles, specifically the relationship sinA/a = sinB/b = sinC/c. The original poster seeks assistance in understanding this proof.
The discussion is currently focused on establishing the rules for requesting help, with some participants emphasizing the need for the original poster to demonstrate an attempt at the problem. There is a recognition of the need for clearer communication regarding the problem statement.
Participants note the forum's guidelines regarding homework help, which require that a questioner show effort before receiving assistance. This has led to a focus on the original poster's need to clarify their question and provide an attempt.
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Sofia_S said:"Prove that in a triangle it is in effect sinA/a=sinB/b=sinC/c