Triangle Proof: Sin Rule for Vectors in Exercise Routine

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Homework Help Overview

The discussion revolves around proving the sine rule for triangles, specifically the relationship sinA/a = sinB/b = sinC/c. The original poster seeks assistance in understanding this proof.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants question the clarity of the original poster's request and seek to clarify what is meant by "it" in the context of the proof. There is an emphasis on ensuring that an attempt has been made before providing help.

Discussion Status

The discussion is currently focused on establishing the rules for requesting help, with some participants emphasizing the need for the original poster to demonstrate an attempt at the problem. There is a recognition of the need for clearer communication regarding the problem statement.

Contextual Notes

Participants note the forum's guidelines regarding homework help, which require that a questioner show effort before receiving assistance. This has led to a focus on the original poster's need to clarify their question and provide an attempt.

Sofia_S
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"Prove that in a triangle it is in effect sinA/a=sinB/b=sinC/c

Please help me...:confused:
 
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Sofia: In order to receive help you must show that you have attempted this problem. It would also help matters if you would properly state the question.

apmcavoy: I've soft deleted your post. I'll restore it once Sofia completes the problem. We do not offer homework help until an attempt is shown. If a student has no clue on how to start a problem then it would be best to ask some guiding questions. And under no circumstances should a complete solution be offered.

You both agreed to these rules, which I will reproduce here for your review:

Homework Help:
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Sofia_S said:
"Prove that in a triangle it is in effect sinA/a=sinB/b=sinC/c

What do you mean by "it"?
 
does he mean, prove the sine rule for a triangle?
 
Ok :) You have right... I will return with the exercise.
Thanks :)
 

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