prasanna
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Hey !
Please help me out with this problem.
A hollow sphere of mass m is released from top on an inclined plane of inclination [tex]\theta[\tex].<br /> <b>(a) What should be the minimum coefficient of friction between the sphere and the plane to prevent skidding?</b><br /> I did this:<br /> <br /> mgsin[tex]\theta[\tex] - f = ma ________ 1<br /> (f is frictional force)<br /> <br /> torque = I[tex]\alpha[\tex] = r X f <br /> (symbols stand for their usual meanings)<br /> <br /> r*f = [tex]\frac{2mr^2}{\frac{a}{r}}[\tex]<br /> <br /> f = (2/3)ma _______2<br /> <br /> Subst. in 1 ,<br /> a= (3/5)gsin[tex]\theta[\tex] ______ 3<br /> <br /> subst. both 2 and 3 in 1,<br /> <br /> f = (2/5) mgsin[tex]\theta[\tex]<br /> but,<br /> [tex]\mu[\tex]mgcos[tex]\theta[\tex] = f = (2/5)mgsin[tex]\theta[\tex]<br /> <br /> [tex]\mu[\tex] = (2/5) tan [tex]\theta[\tex]<br /> <br /> this matches with the textbook answer.<br /> <br /> (<b>b) Find the Kinetic Energy of the ball as it moves down a length L on the incline if the friction coefficient is half the value calculated in part(a).</b><br /> I did this :<br /> <br /> [tex]\mu[\tex] = (1/5) tan [tex]\theta[\tex]<br /> <br /> f = [tex]\mu[\tex]mgcos[tex]\theta[\tex] <br /> <br /> putting this in 1(of part a)<br /> <br /> a = (4/5) g sin[tex]\theta[\tex]<br /> <br /> torque = I[tex]\alpha[\tex] = [tex]\frac{2mr^2}{3}[\tex]<br /> [tex]\alpha[\tex] = [tex]\frac{3gsin\theta}{10r}[\tex]<br /> <br /> KE = (1/2)mv^2 + (1/2)I[tex]\omega^2[\tex]<br /> <br /> v^2 = 2aL = (8/5) gLsin[tex]\theta[\tex]<br /> <br /> [tex]\omega^2[\tex] = 2[tex]\alpha\theta[\tex]<br /> <br /> i found [tex]\omega^2[\tex] = (6gLsin[tex]\theta[\tex]) / (20[tex]\pi\r^2[\tex]<br /> <br /> I get <br /> <br /> KE = (4/5) mgLsin[tex]\theta[\tex] + mmgLsin[tex]\theta[\tex] / 2[tex]\pi[\tex]<br /> <br /> KE = <b>0.831 </b> * mgLsin[tex]\theta[\tex] <br /> <br /> But the answer in the book is (7/8) mgLsin[tex]\theta[\tex] <br /> which is <b>0.875 </b> mgLsin[tex]\theta[\tex] <br /> <br /> <br /> Where did I go wrong?[/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex]
Please help me out with this problem.
A hollow sphere of mass m is released from top on an inclined plane of inclination [tex]\theta[\tex].<br /> <b>(a) What should be the minimum coefficient of friction between the sphere and the plane to prevent skidding?</b><br /> I did this:<br /> <br /> mgsin[tex]\theta[\tex] - f = ma ________ 1<br /> (f is frictional force)<br /> <br /> torque = I[tex]\alpha[\tex] = r X f <br /> (symbols stand for their usual meanings)<br /> <br /> r*f = [tex]\frac{2mr^2}{\frac{a}{r}}[\tex]<br /> <br /> f = (2/3)ma _______2<br /> <br /> Subst. in 1 ,<br /> a= (3/5)gsin[tex]\theta[\tex] ______ 3<br /> <br /> subst. both 2 and 3 in 1,<br /> <br /> f = (2/5) mgsin[tex]\theta[\tex]<br /> but,<br /> [tex]\mu[\tex]mgcos[tex]\theta[\tex] = f = (2/5)mgsin[tex]\theta[\tex]<br /> <br /> [tex]\mu[\tex] = (2/5) tan [tex]\theta[\tex]<br /> <br /> this matches with the textbook answer.<br /> <br /> (<b>b) Find the Kinetic Energy of the ball as it moves down a length L on the incline if the friction coefficient is half the value calculated in part(a).</b><br /> I did this :<br /> <br /> [tex]\mu[\tex] = (1/5) tan [tex]\theta[\tex]<br /> <br /> f = [tex]\mu[\tex]mgcos[tex]\theta[\tex] <br /> <br /> putting this in 1(of part a)<br /> <br /> a = (4/5) g sin[tex]\theta[\tex]<br /> <br /> torque = I[tex]\alpha[\tex] = [tex]\frac{2mr^2}{3}[\tex]<br /> [tex]\alpha[\tex] = [tex]\frac{3gsin\theta}{10r}[\tex]<br /> <br /> KE = (1/2)mv^2 + (1/2)I[tex]\omega^2[\tex]<br /> <br /> v^2 = 2aL = (8/5) gLsin[tex]\theta[\tex]<br /> <br /> [tex]\omega^2[\tex] = 2[tex]\alpha\theta[\tex]<br /> <br /> i found [tex]\omega^2[\tex] = (6gLsin[tex]\theta[\tex]) / (20[tex]\pi\r^2[\tex]<br /> <br /> I get <br /> <br /> KE = (4/5) mgLsin[tex]\theta[\tex] + mmgLsin[tex]\theta[\tex] / 2[tex]\pi[\tex]<br /> <br /> KE = <b>0.831 </b> * mgLsin[tex]\theta[\tex] <br /> <br /> But the answer in the book is (7/8) mgLsin[tex]\theta[\tex] <br /> which is <b>0.875 </b> mgLsin[tex]\theta[\tex] <br /> <br /> <br /> Where did I go wrong?[/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex][/tex]