Why Can't I Solve This Complex Math Equation?

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Homework Help Overview

The discussion revolves around solving a complex algebraic equation involving rational expressions. The original poster expresses difficulty in reaching the correct solutions, which are suggested to be x=3 and x=3/2.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the use of the least common denominator (LCD) and the simplification of the equation. Some suggest multiplying through by the LCD to eliminate fractions, while others focus on ensuring the denominator is consistently defined. There are questions about the correctness of the derived quadratic equations and the resulting solutions.

Discussion Status

There is an ongoing exploration of the algebraic manipulations involved in solving the equation. Some participants have offered guidance on how to proceed with the problem, while others are questioning the accuracy of their calculations and the derived quadratic equations.

Contextual Notes

Participants note that x cannot equal 2 or -2 due to the denominators in the original equation. There is also mention of potential errors in calculations leading to different quadratic forms and solutions.

aisha
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I tried to do this problem soo many times but can't even get close to the answer, I don't know what to do.

[(x)/(x-2)]+2=[(5x)/(x+2)]+[(3x+1)/(x^(2)-4)]

ok I know the LCD is (x+2)(x-2) and that x^(2)-4 is a perfect square that can be written as (x-2) (x+2)

But I can't get the solution it says x=3, 3/2

PLEASE HELP ME SOMEONE :confused:
 
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dear aisha

just make sure that the denominator is equal to x²-4 everywhere...
then you can forget about it (ofcourse x can't be 2 or -2)


like this :

[(x)(x+2)+2(x²-4)=[(5x)(x-2)+[(3x+1)]

Then solve for x...

can you go on from here ?

regards
marlon
 
If you multiply through by the LCD, you'll get:

(x/(x-2))(x-2)(x+2) + 2(x^2-4) = (5x/(x+2))(x-2)(x+2) + ((3x+1)/(x^2-4))(x+2)(x-2)

Simplifying gives you

x(x+2) + 2(x^2 - 4) = 5x(x-2) + (3x+1)

Multiply it out, collect similar terms, and you'll have a quadratic. That can be factored, or you can use the Quadratic Formula. Don't forget to distribute minus signs.

Does that help?
 
Diane_ said:
If you multiply through by the LCD, you'll get:

(x/(x-2))(x-2)(x+2) + 2(x^2-4) = (5x/(x+2))(x-2)(x+2) + ((3x+1)/(x^2-4))(x+2)(x-2)

Simplifying gives you

x(x+2) + 2(x^2 - 4) = 5x(x-2) + (3x+1)

Multiply it out, collect similar terms, and you'll have a quadratic. That can be factored, or you can use the Quadratic Formula. Don't forget to distribute minus signs.

Does that help?

YES THAT HELPS, BUT The quadratic formula I got after multiplied out and collected the like terms was -2x^(2)-x+1 and this factored out and x=-1/2 or x=-1 but the solutions were x=3, 3/2 am I wrong or is the solution wrong?
 
I think you're off somewhere. The quadratic I ended up with was

2x^2 - 9x + 9 = 0

which has the "proper" solutions. It's probably a simple math error. Go back through it and check it.

Unsolicited advice: I have found that students often make those little errors because they're trying to go too fast. I know that the grunt work of algebra can be snore-inducing, but you need to take it slowly at first. Speed comes with experience, and experience is what you're lacking right now. You'll get there, though. All it takes is time. :) </mommy-mode>
 
Thanks Diane I got it FINALLY :smile:
 

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