Calculating Partial Pressures, Keq

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Discussion Overview

The discussion revolves around the concept of calculating partial pressures in the context of chemical equilibrium. Participants explore the reasons why certain initial partial pressures may be zero, examining both theoretical and practical implications.

Discussion Character

  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant expresses understanding of setting up equilibrium tables but questions why some initial pressures are zero.
  • Another participant asserts that an initial partial pressure is zero if the corresponding chemical compound does not exist at the start of the reaction.
  • A different viewpoint suggests that there are two specific reasons for a zero initial partial pressure: it is either a product of the reaction or it is non-volatile with negligible vapor pressure.
  • Participants acknowledge the second reason for zero initial pressure, indicating a refinement of understanding among them.

Areas of Agreement / Disagreement

There is some agreement on the reasons for zero initial partial pressures, but the discussion includes differing interpretations of the conditions under which these pressures are considered zero.

Contextual Notes

Participants do not fully explore the implications of their claims, and the discussion lacks a comprehensive analysis of the conditions that lead to zero initial pressures.

relativitydude
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We're doing chemical equillibrium and I think I pretty much have figured out how to set the table of initial, change and equilibrium pressures. However, i.e. how to arrange my Xs.

However, I do not understand some examples why some initial pressures are simply 0 ATM.
 
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The only reason why the initial partial pressure due to a chemical compound is zero is that,at the initial moment of time,it doesn't exist,so the partial pressure due to it has to be zero.I mean,if that compound were there from the start,wouldn't the pressure due to it be different from zero...? :wink:

Daniel.

P.S.I assume a similar analysis can be made for final states in a chem.reaction.
 
Thank you, so, it is zero unless otherwise stated.
 
No, there are only two reasons for something to have a zero initial partial pressure :

1. It is a product of the reaction, so at t=0, if X(A)=0, P(A) = 0
2. It is non-volatile, ie : its vapor pressure is negligible compared to the total pressure.
 
Yes,Gokul is again,right.The second option didn't occur to me at all...

Daniel.
 

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