Mixing water at different temperatures
Hello all,
I'm having trouble solving the given problem. "Assuming that no heat is lost to the surrroundings, what will be the final temperature when 1 kg of water at 10°C is mixed with 5 kg of water at 80°C" Taking the mean of the 2 fluids will not help here since their mass is different. I don't know any other formula regarding such problems. Thank You, ~MoniMini 
Re: Mixing water at different temperatures
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Re: Mixing water at different temperatures
I found the specific heat capacity online. http://www.engineeringtoolbox.com/wa...iesd_162.html
The heat capacity barely changes from 10 to 80 degrees. But if you wanted to factor the heat capacity change, you could integrate the heat capacity across temperature to get internal energy versus temperature per mass. Then add up the initial energies and this is equal to your final energy. 
Re: Mixing water at different temperatures
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I got the correct anser. I don't know how to type in the mathematical symbols and all, but on paper I calculated and the result was 63.8°C which is the correct answer. Thanks again :) ~MoniMini 
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