What is the curl of a electric field?
This should be simple but I know I'm going wrong somewhere and I can't figure out where.
The curl of a electric field is zero, i.e. [itex]\vec { \nabla } \times \vec { E } = 0[/itex] Because , no set of charge, regardless of their size and position could ever produce a field whose curl is not zero. But, Maxwell's 3rd Equation tells us that, the curl of a electric field is equal to the negative partial time derivative of magnetic field [itex] \vec {B}[/itex]. i.e. [itex]\vec { \nabla } \times \vec { E } = \frac { \partial }{ \partial t } \vec { B } [/itex] So is the curl zero or is it not? If we equate those two equations we get that the time derivative of magnetic field is zero. What's wrong? What am I missing? 
Re: What is the curl of a electric field?
Quote:

Re: What is the curl of a electric field?
Oh. Thanks. Got it. Sometimes things as simple as this slip off.

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