Physics Forums

Physics Forums (http://www.physicsforums.com/index.php)
-   Classical Physics (http://www.physicsforums.com/forumdisplay.php?f=61)
-   -   Diffraction and intensity of fringes (http://www.physicsforums.com/showthread.php?t=674193)

question dude Feb24-13 03:17 PM

Diffraction and intensity of fringes
 
I'm not sure if I've understood my textbook correctly. Can you tell me if my current understanding is correct:

- in a single slit diffraction theres a wide central fringe which is twice as wide as all the other outer fringes

- if we had a double slit diffraction instead of a single slit, we would see fringes within the area that would've been occupied by the wide central fringe


Below is a diagram in my textbook showing intensity distribution of young's fringes, I don't really understand it. Is the blue line supposed to represent the fringes of a single slit diffraction, and the solid red line is representing the fringes of a double slit? I also don't understand at all what the dashed lines in the background are about :confused:

http://www.thestudentroom.co.uk/atta...hmentid=199818


(btw this is all high school level physics)

Philip Wood Feb24-13 05:00 PM

Re: Diffraction and intensity of fringes
 
Your understanding is correct. I think your textbook diagram is confusing, and partly wrong. I'll explain.

I think the dotted red line is supposed to represent a two source pattern with no superimposed diffraction effects. It is wrong because (1) it omits the central fringe (2) it makes the bright fringes too sharp. The intensity should follow a 'cos squared' graph, which is sinusoidal in shape. This implies that at mid-intensity (halfway up the vertical axis) the widths of bright and dark fringes should be equal. They don't seem to be.

The red solid line is the single slit diffraction pattern for a slit with a width of 2s, in which s is the distance between the slit centres used for the two slit graph. I find this confusing, because slits of this width couldn't have a separation s between their centres without merging into one wide slit. I suppose that the diagram makes no claim that the red dotted line and the red solid line should apply to the same set-up, but I'd rather they did.

The blue line is the single slit diffraction pattern for a slit with a width of (2/3)s. I've no quarrel with this: two slits of this width, with centres separated by s, would not merge, and could be used to produce Young's fringes, but there seems to be no graph which shows the 'modulation' of the Young's fringes by the diffraction 'envelope'.

question dude Feb24-13 07:02 PM

Re: Diffraction and intensity of fringes
 
Quote:

Quote by Philip Wood (Post 4284316)
Your understanding is correct. I think your textbook diagram is confusing, and partly wrong. I'll explain.

I think the dotted red line is supposed to represent a two source pattern with no superimposed diffraction effects. It is wrong because (1) it omits the central fringe (2) it makes the bright fringes too sharp. The intensity should follow a 'cos squared' graph, which is sinusoidal in shape. This implies that at mid-intensity (halfway up the vertical axis) the widths of bright and dark fringes should be equal. They don't seem to be.

sorry I don't quite understand what this is

Quote:

Quote by Philip Wood (Post 4284316)
The red solid line is the single slit diffraction pattern for a slit with a width of 2s, in which s is the distance between the slit centres used for the two slit graph.

how comes the solid red line is not a double slit diffraction pattern?

because thats what it appears me. There are three fringes from that solid red line occupying the space inside a wide central fringe (from the blue line)

Quote:

Quote by Philip Wood (Post 4284316)
I find this confusing, because slits of this width couldn't have a separation s between their centres without merging into one wide slit.

I didn't notice this until you've point it out here. Yeah that is impossible, the distance between the two slit centre must to be greater than the slit width. It makes no sense.

Philip Wood Feb25-13 06:23 AM

Re: Diffraction and intensity of fringes
 
What I said about the red solid line in my earlier post was wrong. It is supposed to represent the two source (red dotted) pattern 'modulated' by the blue single slit pattern. Sorry.

"a two source pattern with no superimposed diffraction effects": this is what you'd get if the slits were much smaller than a wavelength in width, and so radiated equally in all 'forward' directions, up to 90 either side of the normal.

question dude Feb25-13 11:46 AM

Re: Diffraction and intensity of fringes
 
Quote:

Quote by Philip Wood (Post 4284917)
What I said about the red solid line in my earlier post was wrong. It is supposed to represent the two source (red dotted) pattern 'modulated' by the blue single slit pattern. Sorry.

thats okay, so this would explain the thing about the slit width appearing to not make sense

Quote:

Quote by Philip Wood (Post 4284917)
"a two source pattern with no superimposed diffraction effects": this is what you'd get if the slits were much smaller than a wavelength in width, and so radiated equally in all 'forward' directions, up to 90 either side of the normal

theres no diffraction for this?

so what is the reason why the intensity of fringes normally peak at the centre and then decrease further outwards?



and also I've just found these two diagrams on the web:


http://www.colorado.edu/physics/phys.../Image2106.gif

http://www.colorado.edu/physics/phys.../Image2109.gif

is this correct:

the first diagram shows diffraction fringes

the second diagram shows both diffraction AND interference fringes


All times are GMT -5. The time now is 07:44 AM.

Powered by vBulletin Copyright ©2000 - 2014, Jelsoft Enterprises Ltd.
© 2014 Physics Forums