The incredible lifting machine heat loss?

Click For Summary
SUMMARY

The discussion centers on the discrepancies between the work calculated using gravitational potential energy (mgh) and the work represented on a pressure-volume (P-V) graph for the Incredible lifting machine. Participants explore the implications of heat loss in the system, questioning the factors that contribute to the difference in work calculations. The conversation highlights the importance of understanding thermodynamic principles and energy conservation in mechanical systems.

PREREQUISITES
  • Understanding of gravitational potential energy (mgh)
  • Familiarity with pressure-volume (P-V) diagrams
  • Basic knowledge of thermodynamics and heat transfer
  • Concept of mechanical energy conservation
NEXT STEPS
  • Research the principles of thermodynamics related to heat loss in mechanical systems
  • Study the relationship between work done and energy conservation in lifting machines
  • Examine real-world applications of P-V graphs in engineering
  • Learn about the factors affecting efficiency in mechanical systems
USEFUL FOR

Mechanical engineers, physics students, and anyone interested in the principles of energy transfer and efficiency in lifting machines.

tubworld
Messages
38
Reaction score
0
the incredible lifting machine heat loss??

While stumbling upon this website on the Incredible lifting machine,

http://tigre.ucr.edu/dipen/phy11/heat.htm
I was wondering what could be some of the reasons why the work down calculated as in mgh does not equal to the work done under the pv graph?

I thought it should be the same? if not, that means there is heat loss by via what means?
 
Last edited by a moderator:
Physics news on Phys.org
tubworld said:
While stumbling upon this website on the Incredible lifting machine,
http://tigre.ucr.edu/dipen/phy11/heat.htm
I was wondering what could be some of the reasons why the work down calculated as in mgh does not equal to the work done under the pv graph?
I thought it should be the same? if not, that means there is heat loss by via what means?
What suggests to you that the increase in potential mechanical energy of the system is not equal to [itex]\int Pdv[/itex]?

AM
 
Last edited by a moderator:

Similar threads

  • · Replies 11 ·
Replies
11
Views
8K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
22K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
7K
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
29
Views
6K