Find the curvature at the point P:
f : [0;2] IR^2 , f (t) = 2t,4 −2t^3 , P(2,2)
i subs 2x=0 then x=0 and 2y=2 then y=1
t=(0,1)
then i perform the curvature calculation.however,i'm confuse that in this case i have to subs t=1 to get a value instead of zero.
If the value t=(2 ,3) or others, which one should i choose??
