sdekivit

[tex]K_{w} = \left[ H^{+}_{(aq)} \right] \left[OH^{-}_{(aq)} \right][/tex]

It follows automatically that, when [tex]K_{W} = 1.0 \cdot 10^{-14}[/tex], [tex]pH + pOH = 14[/tex], and more general:

[tex] pH + pOH = pK_{W}[/tex]