Thread: Finding the dimensions View Single Post
 P: 46 Whoops, I didn't remember you were looking for real solutions. I don't see why you set $x^3-7x^2+14x-8=12$, since it isn't said that this polynomial is the volume. I'd suggest factorising $(x^3-7x^2+14x-8)$ instead, and reading off the dimensions of the box from the factorization. I think that is what is asked for. edit: Nope that doesn't make sense either. You were of course correct.