Thread
:
Precise definition of a limit
View Single Post
quasar987
#
3
Oct2-06, 09:51 AM
Sci Advisor
HW Helper
PF Gold
P: 4,768
Small detail that is important:
Prove that lim x->-2 (x^2-1)=3
0<|f(x)-L|<epsilon whenever 0<|x-a|<delta
You only want to prove that "|f(x)-L|<epsilon whenever 0<|x-a|<delta".
In other words, f(x) can be = L.