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Precise definition of a limit
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quasar987
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Oct2-06, 09:51 AM
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Small detail that is important:
Prove that lim x->-2 (x^2-1)=3
0<|f(x)-L|<epsilon whenever 0<|x-a|<delta
You only want to prove that "|f(x)-L|<epsilon whenever 0<|x-a|<delta".
In other words, f(x) can be = L.