Quote by Galileo
You've shown that: x+2<1 <=> 5<x2<3
This implies that x2<5, simply because x2<3 means that surely x2<5, so that 5<x2<5, or x2<5.

Alright this kinda clarifies my question, so 5 is like the min? Which would grant 5<x2<5since epsilon can never be E<0  the absolute value is necessary? Sorry if I come off a bit slow, but it's just that I'm trying to justify every step so I completely understand the concept.