Quote by murshid_islam
does the answer come out to be [tex]x^2\cos^{2}x + 2x\sin x + 2\cos x + C[/tex]?

Quote by Gib Z
I did integration by parts a few times, I got [tex]I=\frac{\sin^2 x}{2}  x^2 \cos x[/tex] :D I think thats right.
Note: This ones for x^2 sin x dx.

Neither is correct, but murshid is closer than Gib.