does the answer come out to be [tex]-x^2\cos^{2}x + 2x\sin x + 2\cos x + C[/tex]?

I did integration by parts a few times, I got [tex]I=\frac{\sin^2 x}{2} - x^2 \cos x[/tex] :D I think thats right.

Note: This ones for x^2 sin x dx.