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PrudensOptimus
#2
Jan3-04, 07:38 PM
P: 640
You are making it look harder than it is... Just a 3 step problem.

[tex]\frac{1}{1+sinx} + \frac{1}{1-sinx} = \frac{2}{cos^2(x)}[/tex]
[tex]\frac{2}{(1+sinx)(1-sinx)} = ...[/tex]
[tex]\frac{2}{1 - sin^2(x)} = \frac{2}{cos^2(x)} = 2sec^2(x)[/tex]