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HallsofIvy
HallsofIvy is offline
#6
Feb26-07, 10:40 AM
Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,881
gammamcc, I think you are missing the point. The problem is not to integrate [itex]d^2r/dt^2= 1/r^2[/itex]. He's alread done that. That results in
[tex]v= \frac{dr}{dt}= \sqrt{c_1- \frac{2}{r}}[/tex]
The question is how to integrate that.