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Mar30-07, 06:24 AM   #7
 
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[tex] y=\arctan x [/tex]

[tex] \tan y =x [/tex]

[tex] \frac{d}{dx}\tan y= \frac{1}{\cos^{2}y}\frac{dy}{dx}=1 [/tex]

[tex] \frac{dy}{dx} =\cos^{2} y=\left(\frac{1}{\sqrt{1+x^{2}}}\right)^{2}=\frac{1}{1+x^{2}} [/tex]