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 P: 492 Yep, I could just substitute the $\omega_0$ value into the last equation. Would that then be the final answer for $Z_{IN}(\omega_0)$? Is there any simplification I can do for the j's? $$Z_{IN}\left(\omega_0\right)\,=\,\frac{1}{j(2357)\,0.02}\,+\,9X10^{-6}j(2357)\,+11$$ $$Z_{IN}\left(\omega_0\right)\,=\,11\,+\,\frac{1}{47.14\,j}\,+\,0.0212\,j$$