View Single Post
VinnyCee
#3
Apr11-07, 06:07 AM
P: 492
Yep, I could just substitute the [itex]\omega_0[/itex] value into the last equation. Would that then be the final answer for [itex]Z_{IN}(\omega_0)[/itex]? Is there any simplification I can do for the j's?

[tex]Z_{IN}\left(\omega_0\right)\,=\,\frac{1}{j(2357)\,0.02}\,+\,9X10^{-6}j(2357)\,+11[/tex]

[tex]Z_{IN}\left(\omega_0\right)\,=\,11\,+\,\frac{1}{47.14\,j}\,+\,0.0212\,j[/tex]