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Curl in arbitrary coordinates
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Jun29-07, 03:12 PM
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mathwonk
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and again the second part is zero because of equality of mixed partials and the fact that dr^dt = -dt^dr.
so we get just [df/dt dx/dr] dt^dr + df/dr dx/dt dr^dt]
= [df/dr dx/dt - df/dt dx/dr] dr^dt,