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rocomath
#12
Jan18-08, 11:05 PM
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P: 1,754
Quote Quote by Zack88 View Post
[tex]I=\frac{x^2}{m}\sin{mx}-\frac{2}{m}\left(\frac{-x}{m}\cos{mx}+\int\cos{mx}dx\right)[/tex]
ok where did the last [tex]\int\cos{mx}dx\right)[/tex] come from
By doing Parts again to evaluate ...

[tex]\int x\sin{mx}dx[/tex]