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"No gravity" spin on Earth?
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2Pac
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3
Apr1-04, 07:17 PM
P: 40
Ok. I solved for the velocity using: a=(v^2)/r
so... 9.8=(v^2)/6.378 X 10^6
v=7905m/s
then v=(pi*r*2)/t
t=1.4 hours? can anyone confirm if this is right?