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 P: 11 Many derivations of mercury precession angle per orbit $$\Delta$$$$\Phi$$, equate this to extra angle per orbit $$\delta$$ in excess of $$2\pi$$ that is $$\delta$$ = $$\Delta$$$$\Phi$$ But I am getting this relation $$\sqrt{4\pi\delta}$$= $$\Delta$$$$\Phi$$ from arc length of helix and circular orbit. What am I doing wrong? What is the intution for above approximation? Shouldn't the total angle be less than $$2\pi$$ + $$\Delta$$$$\Phi$$ because planet takes short cut [analagous to hypotenuse length being less than sum of other two sides]