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magma_saber
#1
Nov16-08, 04:45 PM
P: 75
1. The problem statement, all variables and given/known data
Calculate Ea from given info:
ln k = 0 t(sec-1) = 0.0033
ln k = -0.2 t(sec-1) = 0.00335
ln k = -0.4 t(sec-1) = 0.0034

2. Relevant equations
ln k = -(Ea/RT) + ln A


3. The attempt at a solution
I could find Ea if i had the temperature but i'm given the time. I think you can cancel out the ln A with the temperature can't you? But if you do that, Ea would be in J/K*mol, but Ea should be kJ/mol. This is all from a graph btw and the y intercept = -4515.7x + 14.749 and R2 = 0.9964. Am i suppose to treat this as y=mx + b?
1. The problem statement, all variables and given/known data



2. Relevant equations



3. The attempt at a solution
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