1. The problem statement, all variables and given/known data
Calculate E_{a} from given info:
ln k = 0 t(sec^{1}) = 0.0033
ln k = 0.2 t(sec^{1}) = 0.00335
ln k = 0.4 t(sec^{1}) = 0.0034
2. Relevant equations
ln k = (E_{a}/RT) + ln A
3. The attempt at a solution
I could find Ea if i had the temperature but i'm given the time. I think you can cancel out the ln A with the temperature can't you? But if you do that, Ea would be in J/K*mol, but Ea should be kJ/mol. This is all from a graph btw and the y intercept = 4515.7x + 14.749 and R^{2} = 0.9964. Am i suppose to treat this as y=mx + b?
1. The problem statement, all variables and given/known data
2. Relevant equations
3. The attempt at a solution
