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Dividing complex numbersss
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Nov28-08, 05:44 AM
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thomas49th
Dividing complex numbersss
Ahh yes i can see i made a istake in the numerator however I dont see how the denominator can be aČ - 1?:
(a-i)(a+i)
= aČ + ai - ai - iČ
= aČ -1
Does i x i always = 1 regardless of what the sign before it is?
Thanks :)