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Nov28-08, 05:57 AM   #5
 
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Quote by thomas49th View Post
Ahh yes i can see i made a istake in the numerator however I dont see how the denominator can be a² - 1?:
(a-i)(a+i)
= a² + ai - ai - i²
= a² -1

Does i x i always = 1 regardless of what the sign before it is?

Thanks :)
No … (a-i)(a+i)
= a² + ai - ai - i²
= a² + 1.

i x i always = -1 regardless of what the sign before it is!