 Quote by thomas49th
Ahh yes i can see i made a istake in the numerator however I dont see how the denominator can be a² - 1?:
(a-i)(a+i)
= a² + ai - ai - i²
= a² -1
Does i x i always = 1 regardless of what the sign before it is?
Thanks :)
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No … (a-i)(a+i)
= a² + ai - ai - i²
= a² + 1.
i x i always =
-1 regardless of what the sign before it is!