Thread: Dividing complex numbersss View Single Post
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 Quote by thomas49th Ahh yes i can see i made a istake in the numerator however I dont see how the denominator can be a² - 1?: (a-i)(a+i) = a² + ai - ai - i² = a² -1 Does i x i always = 1 regardless of what the sign before it is? Thanks :)
No … (a-i)(a+i)
= a² + ai - ai - i²
= a² + 1.

i x i always = -1 regardless of what the sign before it is!