Thread: Laurent series View Single Post
 Thank you, I have few questions 1. Is it that you choose $(z - i)$ terms because the question specifies it should converge in $0 < |z-i| < R$ ? 2. So $\frac{B}{z + i}$ will be expanded like $\frac{1}{2i} * \frac{1}{1+\frac{z-i}{2i}} = \sum_{n=0}^{\infty}{s^n}$ where $s = \frac{z-i}{2i}$ so the answer to the solution would be $\frac{A}{z-i} + \{expansion\, in\, 2\}$ ? Thanks again