Thread: Laurent series
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krindik is offline
Apr10-09, 11:05 PM
P: 67
Thank you,

I have few questions
1. Is it that you choose [latex] (z - i) [/latex] terms because the question specifies it should converge in [latex] 0 < |z-i| < R [/latex] ?

2. So [latex]\frac{B}{z + i} [/latex] will be expanded like

[latex]\frac{1}{2i} * \frac{1}{1+\frac{z-i}{2i}} = \sum_{n=0}^{\infty}{s^n}[/latex]

[latex] s = \frac{z-i}{2i}[/latex]

so the answer to the solution would be
[latex]\frac{A}{z-i} + \{expansion\, in\, 2\}[/latex] ?

Thanks again