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mmoadi
#10
Oct14-09, 02:36 PM
P: 157
vy= v0y - gt and for t I'm using 1/2 s, which is the time needed for the ball to rise to the max height.
So, vy= 5.9 m/s - (9.8 m/s * 1/2 s)= 1 m/s

And, if I plug this into the Pythagoras formula, the initial velocity should be 13.02 m/s?

As for the angle, is this correct: α= (tan)-(v0y / v0x)= 24.49 ?