vy= v0y  gt and for t I'm using 1/2 s, which is the time needed for the ball to rise to the max height.
So, vy= 5.9 m/s  (9.8 m/s² * 1/2 s)= 1 m/s
And, if I plug this into the Pythagoras formula, the initial velocity should be 13.02 m/s?
As for the angle, is this correct: α= (tan)¹(v0y / v0x)= 24.49° ?
