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mmoadi
#14
Oct14-09, 07:21 PM
P: 157
So it continues:
"You have already found v0 (the launch speed)." Does this mean that the v0 is -3.9 m/s?

vb= sqrt(vbx + vby)= sqrt(169 + 15.21)= 13.57 m/s
Is vb the final velocity of the ball?

As for the angle, I think that the relationship is tan(angle)= vby / vbx, which gives us an angle of -16.7?