Quote by strangerep
Except that the a/c operators in QFT2 are not bonafide operators, but are really
operatorvalued distributions. Hence fields constructed as linear combinations of them
are also operatorvalued distributions. Hence QFT2 suffers exactly the same "illdefined
equalpoint multiplication of distributions" mathematical problem as QFT1.

Could you give an example in which a product of a/c operators or quantum fields is "illdefined"?