Thread: Activation Energy View Single Post
 P: 1,779 Hi Also, since k is a function of temperature, if $$k_{1}$$ and $$k_{2}$$ are rate constants measured at $$T_{1}$$ and $$T_{2}$$ we have from the Arrhenius Equation, $$\frac{k_{2}}{k_{1}} = e^{\frac{E_{a}}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})}$$ So actually this eliminates the need to know the frequency factor A. All you need to know is the rate constants measured at two different temperatures or even their ratio $$\frac{k_{2}}{k_{1}}$$ and that is enough to get $$E_{a}$$, which turns out to be, $$E_{a} = R\frac{T_{1}T_{2}}{T_{2}-T_{1}}log_{e}\frac{k_{2}}{k_{1}}$$ Please make note of this correction in my previous post.