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housemartin
housemartin is offline
#2
Jul21-10, 02:34 AM
P: 87
make an experiment ;]
if you push box A with force F, all four boxes will accelarate at the same rate, with acceleration given by:
a = F/(Ma+Mb+Mc+Md)
box D will not start to move away from D, unless there is something else involved besides boxes and force you apply (like some bomb between box C and D which explodes ;]).
Net force on each box will be the force, that makes this box to accelerate at a:
net_F(on D) = Md*a = Md*F/(Ma+Mb+Mc+Md)
excact forces on D when added must give net_F(on D). But there is only one force acting on D, that is force exerter by box C.
On box C there are two forces - one by box B, o ther by box D. According to Newton's third law force by box D is equal in magnitude to the force by C to D, but acting in opposite direction. Using this you can find force by box B on box C. And similarly forces on B and A.