P: 40

1. The problem statement, all variables and given/known data
Find the continuous points P and the differentiable points Q of the function [tex]f[/tex] in [tex]{R}^3[/tex], defined as
[tex]f(0,0,0) = 0[/tex]
and
[tex]f(x,y,z) = \frac{xy(1\cos{z})z^3}{x^2+y^2+z^2}, (x,y,z) \ne (0,0,0)[/tex].
2. Relevant equations
3. The attempt at a solution
If you want to look at the limit I'm having trouble with, just skip a few paragraphs. I'm mostly including the rest in case anyone is in the mood to point out flaws in my reasoning.
Differentiating [tex]f[/tex] with respect to x, y and z, respectively (when [tex](x,y,z) \ne (0,0,0)[/tex] will make it apparent that all three partials will contain a denominator of [tex](x^2+y^2+z^2)^2[/tex] and a continuous numerator. Thus, these partials are continuous everywhere except in [tex](0,0,0)[/tex], and it follows that [tex]f[/tex] is differentiable, and consequently, also continuous in all points [tex](x,y,z) \ne (0,0,0)[/tex].
Investigating if [tex]f[/tex] is differentiable at [tex](0,0,0)[/tex], we investigate the limit
[tex]\lim_{(h_1,h_2,h_3) \to (0,0,0)}{\frac{f(h_1,h_2,h_3)  f(0,0,0)  h_1 f_1(0,0,0)  h_2 f_2(0,0,0)  h_3 f_3(0,0,0)}{\sqrt{{h_1}^2 + {h_2}^2 + {h_3}^2}}} = \lim_{(h_1,h_2,h_3) \to (0,0,0)}{\frac{h_1 h_2 (1\cos{h_3})  {h_3}^3}{({h_1}^2 + {h_2}^2 + {h_3}^2)^{3/2}}}.[/tex]
Evaluating along the line [tex]x = y = z[/tex], that is, [tex]h_1 = h_2 = h_3[/tex], it is found after a bit of work and one application of l'Hôpital's rule that the limit from the right does not equal the limit from the left, and hence, [tex]f[/tex] is not differentiable in [tex](0,0,0)[/tex].
To prove continuity of [tex]f[/tex], we want to show that [tex]\lim_{(x,y,z) \to (0,0,0)}f(x,y,z) = 0[/tex]. Since I haven't found any good counterexamples to this, I've tried to prove it with the epsilondelta definition instead, with little luck.
We see that
[tex]f(x,y,z)  0 = \left\frac{xy(1\cos{z})z^3}{x^2 + y^2 + z^2}\right \le \left\frac{xy(1\cos{z})z^3}{z^2}\right,[/tex]
getting me nowhere.
Trying with spherical coordinates instead, we get
[tex]f(x,y,z)0 = \left\frac{{\rho}^2 {\sin^2 \phi} \cos{\theta} \sin{\theta} (1\cos{(\rho \cos{\phi})})  {\rho}^3 \cos^3 {\phi}}{{\rho}^2 \sin^2 {\phi} \cos^2 {\theta} + {\rho}^2 \sin^2 {\phi} \sin^2 {\theta} + {\rho}^2 \cos^2 {\phi}}\right = \left\sin^2 {\phi} \cos{\theta} \sin{\theta} (1\cos{(\rho \cos{\phi})})  \rho \cos^3 {\phi}\right.[/tex]
I'm not sure how to proceed. Suggestions?

