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PF Gold
P: 1,481
 Quote by derekbeau P = Mgh P = 1710000 * 9.81 * 100 and I got 1677510000 (watts?) Well that wasnt the right answer, so i tried converting to kilowatt-hours 1677510000 W / 3600000 J = 465.975 kWh Still not right. I think my problem is because either the height of the water is changing, or i am using an incorrect height. I dont know. But any help would be great. (it is due tomorrow) Thanks
$$W=Q*\Delta P_o$$; where [Q]=[m^3/s] is the volumetric flow; [P_o]=[Pa] is the total pressure in both sides of the turbine.
In your case: $$P_{oentrance}-P_{oexit}=P_a+\rho g H$$-P_a[/tex]
So that: $$W=\rho g H Q$$ where the units are:
$$[W]=\frac{Kg}{m^3} * \frac{m}{s^2}* m *\frac{m^3}{s}=\frac{J}{s}=Watt$$