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Solve for x log3 (x-2) + log3 (x-4) = 7

 Quote by nae99 1. The problem statement, all variables and given/known data i have been trying to do this ques. 2 days now and still cant get the ans. help plz Solve for x log3 (x-2) + log3 (x-4) = 7 2. Relevant equations 3. The attempt at a solution log3 (x-2) (x-4) = 7
 Quote by nae99 what does that mean
His hint was to use the inverse function of the logarithm as your first step.

So if you were working with log base 2, you would raise both sides to the exponent power of 2....

$$log_2 (x) = 5$$

$$2^{log_2 (x)} = 2^5$$

...and simplify the lefthand side...