Solve for x log3 (x-2) + log3 (x-4) = 7

[nae99]

(-6)^2 = -36

-4*(1)*(-2179) = 8716

so should it be √ -36 + 8716 / 2

 

[nae99]

no,

what is (-6)² ?

What is -4*(1)*(-2179) ?

How were you taking the square root of negative numbers?

(-6)^2 = 36

-4*(1)*(-2179) = 8716

 

[BloodyFrozen]

Or you can use change of base. It might be a little tedious though...

 

[SammyS]

Or you can use change of base. It might be a little tedious though...

Have you looked at the previous posts in this thread? Change of base would appear to be a huge stretch if we are having this trouble with plugging into the quadratic formula.

 

[nae99]

Have you looked at the previous posts in this thread? Change of base would appear to be a huge stretch if we are having this trouble with plugging into the quadratic formula.

i don't have any how to plug it into anything, so I am clueless of what you u are talking about

 

[BloodyFrozen]

Have you looked at the previous posts in this thread? Change of base would appear to be a huge stretch if we are having this trouble with plugging into the quadratic formula.

Yeah, true...

(-6)^2 = -36
-4*(1)*(-2179) = 8716

so should it be √ -36 + 8716 / 2

(-6)^2 = (-1)^2*(6)^2 = 36
-6^2 = -1*(6)^2 = -36

P.S. Nae99, may I ask what kind of Pre-calc class (college, high school) you are taking?

 

[nae99]

Yeah, true...



(-6)^2 = (-1)^2*(6)^2 = 36
-6^2 = -1*(6)^2 = -36

P.S. Nae99, may I ask what kind of Pre-calc class (college, high school) you are taking?

college