Maximum force on stacked boxes, when we don't want the boxes to slip.

tomas123

aah I get it!

the sum of F on M1 is 9.8N. Divided by 3kg = 3.267 m/s2.

Sum of F on whole system = force by rope - friction
(7kg * 3.267 m/s2) +13.72 = force by rope
36.589 = force by rope

Thank you!!

tomas123	aah I get it! the sum of F on M1 is 9.8N. Divided by 3kg = 3.267 m/s2. Sum of F on whole system = force by rope - friction (7kg * 3.267 m/s2) +13.72 = force by rope 36.589 = force by rope Thank you!!