Maximum force on stacked boxes, when we don't want the boxes to slip.
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Sep26-11, 04:49 PM
aah I get it!
the sum of F on M1 is 9.8N. Divided by 3kg = 3.267 m/s2.
Sum of F on whole system = force by rope - friction
(7kg * 3.267 m/s2) +13.72 = force by rope
36.589 = force by rope