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LCKurtz is offline
Sep29-11, 10:37 PM
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Quote Quote by MegatronX View Post

----c C
I was hoping there was a more straight forward/easy way to find the center when two points are know and all the angles/lengths are known.

Thanks in advance for any help
Let d be the distance from A to B. If you know A and B you can find its mid-point M. Lets say the vector AB is <s,t>. Then a vector perpendicular to it is <-t,s>. Divide that vector by its length and call the resulting vector V. If you know the radius r you can calculate the height h of your triangle with the Pythagorean theorem using hypotenuse r and leg d/2.

Then if O is the origin, the coordinates of the center are OA+ (1/2)ABą hV, with the sign chosen depending on which side of AB the center is on.