Relativistic Velocity: Speed Limits & Ranges Explained

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Relativistic velocity refers to speeds where relativistic effects become significant, typically when the Lorentz factor gamma is substantially greater than 1. While all velocities are technically relativistic, noticeable effects arise at speeds approaching a significant fraction of the speed of light. For example, a speed of 0.1c yields a gamma of about 1.005, which may not be important in many contexts but is critical for systems like GPS satellites. The kinetic energy of particles must also account for relativistic corrections when speeds are high enough to deviate from classical calculations. Understanding these principles is essential for accurate applications in physics and engineering.
nelufar
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Which velocity can be said to be relativistic velocity? I mean is there any range beyond which velocities can be called as relativistic velocities?
 
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All velocities are relativistic, but relativistic effects will not be easily noticeable until the speed is large enough to make

\gamma=\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}

(where v is the speed, and c is the speed of light)

significantly larger than 1.

An example: suppose that v=0.1c, i.e. 10% of the speed of light. Then gamma is about 1.005. Is that significantly larger than 1? That depends on that you're doing. Sometimes a 0.5% correction to the non-relativistic result isn't important, and sometimes it is.
 
Is same true for relativistic energies also?
 
The kinetic energy of a particle is E_{kin.}=(\gamma -1)mc^2 if this deviates substantially from classical kinetic energy you should use the relativistic result.

So you could use as a criterium: if 2 (\gamma -1)c^2/v^2 is significantly larger than 1 you deal with relativistic velocities...
 
Consider the orbital speed of a satellite or spacecraft : ~17,000mph. For an astronaut, this is not a relativistic velocity, meaning he won't notice the time dilation on his watch from takeoff to landing. For a GPS satellite, however, this is a relativistic velocity and must be accounted for in its functioning in order for GPS positions to be accurate.
 
nelufar said:
Is same true for relativistic energies also?
To see the answer to your question it helps to use the series expansion

\frac{1}{\sqrt{1-x}}=1+\frac{1}{2}x+\frac{3}{8}x^2+\frac{5}{16}x^3+\dots

The kinetic energy is

(\gamma-1)mc^2=\bigg(1+\frac{1}{2}\bigg(\frac{v^2}{c^2}\bigg)+\frac{3}{8}\bigg(\frac{v^2}{c^2}\bigg)^2+\frac{5}{16}\bigg(\frac{v^2}{c^2}\bigg)^3+\dots-1\bigg)mc^2=\frac12mv^2\bigg(1+\frac34\bigg(\frac{v^2}{c^2}\bigg)+\frac58\bigg(\frac{v^2}{c^2}\bigg)^2+\dots\bigg)

Note that the first term after the last equality sign is just the non-relativistic kinetic energy. The other terms are relativistic corrections to the non-relativistic result. If the speed is large enough these terms can't be ignored.
 
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