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Ah, of course!
Okay, so based on that...
Current of the 8.45 Ω resistor should be (10.971)/(8.45) = 1.3 A
and the 4.11 Ω will be (10.971)/(4.11) = 2.67 A
So the total for the subcircuit will be
.795 A
+.638 A
+1.3 A
+2.67 A
= 5.403 A
....
Would that be correct?
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