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ObviousManiac
#3
Dec14-11, 11:11 PM
P: 37
Ah, of course!

Okay, so based on that...

Current of the 8.45 Ω resistor should be (10.971)/(8.45) = 1.3 A

and the 4.11 Ω will be (10.971)/(4.11) = 2.67 A

So the total for the subcircuit will be

.795 A
+.638 A
+1.3 A
+2.67 A

= 5.403 A

....
Would that be correct?