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cupid.callin
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#4
Jan10-12, 02:46 AM
P: 1,135

Acceleration of Proton (Kinetic Energy & relativity)


Quote Quote by HarleyM View Post
ERest= (1.67x10-27)(3x108)2
ERest= 1.503x10-10

EMoving= mc2/√(1-v2/c2)
=((1.67x10-27)(3x108)2)/√(1-0.9999c2/c2)
=1.503x10-10/√(1-0.9998)
= 1.503x10-10/ 0.0141418
= 1x10 -8 J
Your kinetic energy requires will be E when moving - E when at rest !!

So it will be 10-8 - 1.503*10-10 = 9.85 * 10-9