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:
Acceleration of Proton (Kinetic Energy & relativity)
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Jan10-12, 04:19 AM
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5
ehild
Recognitions:
Homework Help
v=0.9999c. 1-v^2/c^2 =1-0.9999^2. It is better to expand it as (1-0.9999)(1+0.9999) = 1.9999 E-4.
[tex]mc^2=\frac{100 m_0c^2}{\sqrt{1.9999}}[/tex]
KE=mc
2
-m
0
c
2
, about 70 times the rest energy.
ehild