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Jan28-12, 06:40 PM
P: 136
Computing the period of a meteor using two ways.

I'm looking at code that computes the orbit found for a meteor. It computes the period of the meteor as:

a = 13.07 # semi-major axis in AU
P = m.sqrt(a*a*a) # From the program

which yields P = 47.2512586393 Years

If I use the "standard" approach

P = 2*pi*m.sqrt((a*a*a)/mu),

where mu (=GM) is the standard gravitational constant (G*M or GM).
3986004418.0 in km**3/sec**2,

then I get:

P = 703462.683141 # units?

They certainly don't look close. A source I'm looking at says 4*pi*pi/G = 1, but they are talking about solar masses.

So why the large discrepancy? Units?
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